fix(tkfb): is_admin_only 레거시 필터 제거

과거 권한 시스템 잔재인 is_admin_only 필터를 모든 런타임 코드에서 제거.
현재 체계: admin=모든 페이지, 일반 사용자=권한 부여된 페이지만.
DB에서도 is_admin_only = 0으로 통일 (22건 갱신).

Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>
This commit is contained in:
Hyungi Ahn
2026-03-31 07:17:30 +09:00
parent 5ac7af7b04
commit d3cef659ce
3 changed files with 3 additions and 12 deletions

View File

@@ -75,12 +75,10 @@ const DashboardModel = {
`);
if (isAdmin) {
const adminPages = allPages.filter(p => p.is_admin_only);
const normalPages = allPages.filter(p => !p.is_admin_only);
return {
department_pages: normalPages.map(formatPage),
department_pages: allPages.map(formatPage),
personal_pages: [],
admin_pages: adminPages.map(formatPage)
admin_pages: []
};
}
@@ -114,8 +112,6 @@ const DashboardModel = {
const personalPages = [];
for (const page of allPages) {
if (page.is_admin_only) continue;
if (deptPageKeys.has(page.page_key)) {
departmentPages.push(formatPage(page));
} else if (personalPageIds.has(page.id)) {

View File

@@ -19,7 +19,6 @@ const PageAccessModel = {
FROM pages p
LEFT JOIN user_page_access upa ON p.id = upa.page_id AND upa.user_id = ?
LEFT JOIN users granter ON upa.granted_by = granter.user_id
WHERE p.is_admin_only = 0
ORDER BY p.category, p.display_order
`;
@@ -39,7 +38,6 @@ const PageAccessModel = {
is_admin_only,
display_order
FROM pages
WHERE is_admin_only = 0
ORDER BY category, display_order
`;

View File

@@ -95,9 +95,6 @@ router.get('/users/:userId/page-access', requireAuth, async (req, res) => {
ON dpp.department_id = ?
AND (dpp.page_name = CONCAT('s1.', p.page_key) OR dpp.page_name = p.page_key)
LEFT JOIN users u2 ON upa.granted_by = u2.user_id
WHERE p.is_admin_only = 0
OR upa.can_access = 1
OR dpp.can_access = 1
ORDER BY p.display_order, p.page_name
`, [userId, departmentId]);
@@ -232,7 +229,7 @@ router.get('/page-access/summary', requireAuth, async (req, res) => {
u.name,
r.name as role_name,
COUNT(DISTINCT upa.page_id) as accessible_pages_count,
(SELECT COUNT(*) FROM pages WHERE is_admin_only = 0) as total_pages_count
(SELECT COUNT(*) FROM pages) as total_pages_count
FROM users u
LEFT JOIN roles r ON u.role_id = r.id
LEFT JOIN user_page_access upa ON u.user_id = upa.user_id AND upa.can_access = 1